A $\triangle {ABC}$ is rotated in its own plane about point $A$ into position $A'B'C'$.if $AC$ bisects $BB'$ prove that $AB'$ bisects $CC'$

Question

The question is :-

A $\triangle {ABC}$ is rotated in its own plane about point $A$ into position $A'B'C'$.if $AC$ bisects $BB'$ prove that $AB'$ bisects $CC'$

To be clear the main problem is I cant imagine how the figure will be formed .

So please tell the actual figure for the above question so that I could proceed further .

Answer 1

HINT: (According to Michal Adamaszek's correction) Here is a general figure. You can use congruence of $\Delta ABC$ and $\Delta AB'C'$ to prove the statement.

If this one was not enough:

A kite should finish the proof.