All 2D differentiable surfaces conformal to the euclidian metric?

178 Views Asked by At

Is it true that the metric of any continuous differentiable 2D surface is locally conformal to the euclidian metric ? (see equ. (2) below). Can I state something like this in general ? If so, what is the name of the theorem that gives a demonstration ? If it's not general, what are the conditions to make this true ? \begin{align}\tag{1} ds^2 = g_{ij} \, dx^i \, dx^j &\equiv g_{11} \, dx^2 + g_{22} \, dy^2 + 2 \, g_{12} \, dx \, dy \\[12pt] &= \Omega^2(u, v)(du^2 + dv^2). \tag{2} \end{align} The original metric (in coordinates $x$, $y$) is positive definite.