Altitude of tetrahedron?

Question

I'm really curious to know any relationships between the altitude of a tetrahedron and how the foot of this altitude splits the base triangle. For example if you have a tetrahedron PABC with apex P, and then you drop the altitude from P to the opposite base how does it split this base? Is the foot of the altitude the centroid/incenter/orthocenter of the base? Are there any special properties related to this?

Thanks :)

Answer 1

In a general tetrahedron, you can freely move the apex in a plane parallel to the base, so the foot can be any place in the base triangle. No special relations can be inferred from the general case.