Angle of an inscribed quadrilateral with two opposite right angles

84 Views Asked by At

I'm currently writing a program to track the height of the head of a 3d printer using a servo motor and a camera mounted to it. I made a sketch in Solidworks just to visualize better the shape of the system and this is what I did.

enter image description here The camera "eye" is placed at the point "C", always pointing to the head "H" with the servo "S" where the rotation center is, and "B" the printer "bed".

I know the position of the printer head at each moment (BH length) , and the x and y offsets (SB, SC length respectively). What I would like to do is to compute the angle θ of the servo motor to always point to the head.

From this website I got to this formula $\theta = \arccos\left(\frac{x^2+y^2-h^2-a^2}{2\left(xy+ha\right)}\right)$ where $x$ and $y$ are the offsets, $h$ the printed head height, and $a$ the distance between the camera and the head, and $a $is unknown. So I'm wondering how to find $\theta$ if $a$ is not known neither. Thanks!

1

There are 1 best solutions below

0
On BEST ANSWER

Assuming $a=|CH|$, using the Pythagorean theorem, $$|SH|^2=a^2+y^2=x^2+h^2\implies a^2=x^2-y^2+h^2. $$

$$\therefore\; \theta=\cos^{-1}\left(\frac{x^2+y^2-a^2-h^2}{2(xy+ah)}\right)=\cos^{-1}\left(\frac{y^2-h^2}{xy+h\sqrt{x^2-y^2+h^2}}\right)$$