Let X be a non-negative random variable with finite expected value. Can we use Borel Cantelli Lemma to show that X is finite?
2026-03-26 19:17:09.1774552629
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Application of Borel Cantelli Lemma
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Let $(a_n)$ be a monotone-increasing sequence of non-negative numbers. By the Markov's inequality,
$$ \Bbb{P}(X \geq a_n) \leq \frac{\Bbb{E}X}{a_n}. $$
Choose $a_n$ such that $\sum_n \frac{1}{a_n} < \infty$. Then $\sum_n \Bbb{P}(X \geq a_n) < \infty$ and hence by the Borel-Cantelli's lemma,
$$ \Bbb{P}(X \geq a_n \text{ i.o.}) = 0. $$
But if $X(\omega) = \infty$, then we must have $X(\omega) \geq a_n$ infinitely often. Therefore we have $\Bbb{P}(X = \infty) = 0$.
This is simpler than the Borel–Cantelli lemma: if $\Pr(X=\infty)>0$, then $\operatorname{E}(X)=\infty$ by the definition of expectation.
Now suppose $X$ is a discrete random variable equal to the number of events in a sequence $A_1,A_2,A_3,\ldots$ that actually occur. Then one could think of applying Borel–Cantelli. One would have to know that the hypotheses are satisfied.