Approximate Binomial Distribution using normal distribution

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When I was reading "cracking the GRE mathematics subject test" 4th edition page 282, there is a formula regarding approximation of binomial distribution:

In X ~ Binomial(n, p), when n is large, we could use normal distribution to approximate it.

P($a_1$ < X < $a_2$) $\approx$ $\phi$($\dfrac{a_2 - \mu + 0.5}{\sigma}$) - $\phi$($\dfrac{a_1 - \mu - 0.5}{\sigma}$)

I was quite confused about the 0.5 in RHS, I believe the formula should be:

P($a_1$ < X < $a_2$) $\approx$ $\phi$($\dfrac{a_2 - \mu}{\sigma}$) - $\phi$($\dfrac{a_1 - \mu}{\sigma}$)

I am not sure if I am correct. Any comments or help would be greatly appreciated!