When we solve a cubic equation $ax^3+bx^2+cx+d=0$, the roots are supposed to be in the form of radicals in real numbers or complex realm. However, if the discriminant is less than 0, the solution is ended up with roots represented by inverse trigonometric function in most cases. For example, the three roots for $x^3−4x+1=0$ are all in trigonometric form. And the equation $x^3−2x+1=0$ has 1 rational root, and two other roots that could be in radical form if solved by factorization method or inverse trigonometric values if solved by Cardano's solution and trigonometric method. By comparing their decimals, the roots obtained by two different methods are equal. My question is - are there any general ways to convert these inverse trigonometric values to radicals?
2026-04-02 15:48:08.1775144888
Are there any ways to convert inverse trigonometric values to radicals?
93 Views Asked by Bumbble Comm https://math.techqa.club/user/bumbble-comm/detail AtRelated Questions in TRIGONOMETRY
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