Are there "continuous" random variables without a density function?

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Assume you have a random varaible with a cumulation distribution function $F(x)=P(X\le x)$. This function will always be right-continuous, but assume that it also is left-continuous. Then there are no single values which have a positive probability.

Will this random variable always have a probability density function which can be integrated?

By the Radon-Nikodym theorem what we have to show is that the measure induced by $F(x)$ is absolutely continuous with respect to the Lebesgue-measure. However, I do not know how to show this.