Let be $\triangle ABC$ a triangle with its area of $48\text{cm}^{2}$. $M$ is the mid of $[BC]$ and $P$ is the mid of $AM$. We know that $BP \cap AC = \left\{N\right\}$. The question is: how to compute the $\triangle ABN$ area?
I tried to use that the area of $\triangle ABM = 24$ also I tried to compute the mid of $[AC]$ and to try to divide the triangle in more smaller triangles, but no success for the moment.
Any input will be really appreciated.