Area of Square - Comparing squares

Question

The question is:

If the area of a parallelogram $JKLM$ is $n$ and if length of $KN$ is $n+(1/n)$, then find the length of $JM$. (The answer is $n^2 /( n^2+1 )$.)

How would i go about solving this problem ?

Answer 1

The area of a parallelogram (or see on Wikipedia) is the base times the height. The base here is $JM$ and the height is $KN$, so the area is $$KN * JM = n$$

So you have

$$ \left(n + \frac{1}{n}\right)*JM = n $$ Then you solve for $JM$