She (40) is chosen from the population with maximum age 121. Average remaining lifetime at age $x$ is equal $\frac{121-x}{2.4}$ for $x<121$.
He (30) is chosen from the population with maximum age 98. Average remaining lifetime at age $x$ is equal $\frac{98-x}{2.7}$ for $x<98$.
His and her lifespans are independent. Calculate the probability that both of them will live longer than 37 years.
So I have to calculate $_{37}p_{40} \cdot _{37}p_{30}$ but I do not know how to take these probabilities from the average lifetime.
Thanks in advance.