So I have the function $v=10i+4$ where $v$ is the horizontal axis and $i$ is the vertical axis. Please excuse me for such a basic question but I can't work out how to draw this function.
I figure if $v=something +4$ then I know the line intersects the $v$ axis at 4. This won't change the slope of the line, just the starting point.
So I have my starting point at v=4, i=0. I figure $1v=10i$ so I make a mark at $1$ on the $v$ axis and $10$ on the $i$ axis then draw a line from that point to the starting point on the $v$ axis.
However this doesn't seem to be right and I can't work out why. Can someone please explain where I have gone wrong in drawing this graph.
$v=10i+4$ , replace $v$ by $x$ and $i$ by $y$ $\therefore x=10y+4$
$10y=x-4 \Rightarrow y=\frac{x}{10}-\frac{4}{10}$
This is the equation of a straight line with slope=$1/10$ and y-intercept=$-4/10=-2/5$ and x-intercept=$4$
can you draw a line passing through $(0,\large\frac{-2}{5})$ and $(4,0,)$