Bernoulli Trials question involving binomial variables

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In the exercise, X is a binomial variable with n = 6 and p = 0.2. Compute the given probability.(Round your answer to five decimal places.)

P(X = 5)

For this one I did:

(6C5)((.2)^3)((.8)^3)=.024576 which rounded to 5 decimal places is 0.02458

But this is not the correct answer, could someone tell me how to do this problem correctly or where I went wrong?

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The correct equation would be $P(X=r) = \binom{n}{r}p^r (1-p)^{(n-r)}$.

That gives (6C5)((.2)^5)((.8)^1) = 0.001536

You seem to have both exponents for $p$ and $(1-p)$ as $3$ for some reason.