Big Omega Proof for $5^n = \Omega(6^n)$

Question

I got the Big-O ($\mathcal{O}$) proof but I am having troubles with the Big Omega ($\Omega$) proof. I am trying to prove $6^n$ is not the tightest bound for $5^n$. Is this logic true: $7^n$, $8^n$ would be a tighter bound than $6^n$? If that is true then I think I got the answer. If not can someone lead me to the right direction.

Answer 1

Note that $6^n/5^n=1.2^n\rightarrow\infty$ as $n$ gets large, so $5^n$ cannot be big-omega of $6^n$.