I have problems with questions regarding probability with little information given. Is it simpler than it really is? I'm not sure where to begin to start.
For example:
40% of adults receive an email for a magazine subscription over a 12 month period. Consider a random sample of 15 adults:
(1). What is the probability that none of the sample received an email for a magazine subscription?
(2). What is the probability that over half of the sample received an email for a magazine subscription?
Is $n = 15$ or is it 40% of 15, being $n = 6$? How do I start?
Here is a start for (1): Let $X$ be the number who get such an email. Then $X \sim Binom(15, .4)$ You seek $P(X = 0) = (.6)^{15}.$
In R statistical software:
For (2), you want $P(X \ge 7.5) = P(X \ge 8).$ You have not provided any context or shown any attempt, so I don't know whether you are supposed to compute this on a calculator, look it up in a printed binomial table, or do a normal approximation.
$$P(X \ge 8) = \sum_{x=8}^{15} {15 \choose x} (.4)^x (.6)^{15-x} = \,??.$$
Normal approximation: $\mu = np = 15(.4) = 6$ and $\sigma = np(1-p) = 1.897$ $$P(X > 7.5) = P\left(\frac{X-\mu}{\sigma} > \frac{7.5 - 6}{1.897}\right) \approx P(Z > 0.79) = \,??,$$ where $Z$ is standard normal.
Here is a bar chart of the distribution. Values for 0 and beyond 12 are too small to show on the plot.