In the final match a boxer is facing another boxer and is expected to win 48% of the time. In reality they win 80% of the time.
What is the probability of that occurring in 10 matches?
2) In the very next match (in a different tournament), the boxer who won the previous match only wins 40% of the time.
- With the winning rate in the previous match, whats the probability of seeing that winning rate in 10 matches?
How would you go about this problem? I believe this a binomial problem but i do not know what the 48% and 80% are. Is one the varience and the other the expected mean? I dont know what equations i need in order to solve this problem. Also, how could I calculate this on excel. So if someone could guide me through this that would be great.
Both questions are VERY poorly written.
I'm pretty sure that the intention of the first question is for you to calculate the probability of winning exactly 8 matches if the probability of each win is 0.48
$$ P_8 = \binom{10}8 (0.48)^8 (0.52)^2 $$
I can't imagine what it is the second question wants.