I've been struggling to prove this expression literally all day please help.
A'B + A'C + B'C = A'B + B'C
HINT:
$$\begin{align*} A'B+A'C+B'C&=A'B+A'(B+B')C+B'C\\ &=(A'B+A'BC)+(A'B'C+B'C) \end{align*}$$
Now simplify the expressions in parenthesis.
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HINT:
$$\begin{align*} A'B+A'C+B'C&=A'B+A'(B+B')C+B'C\\ &=(A'B+A'BC)+(A'B'C+B'C) \end{align*}$$
Now simplify the expressions in parenthesis.