Prove using Prove algebraically : 1) x'′⊕ y = x⊕y' = (x⊕y)'
2) x⊕1 = x'
3) x⊕x' = 1
4) (A+B)(A'C'+C)(B'+AC') = A'B $(A+B)(A'.C'+C)(B'+AC)' = A'B$
I know x⊕y = xy'+x'y But how do i deal with X'⊕Y? What does that become?
And for 4) I did:
(A+B)[(X+Y)'+C] [B.(AC)']
(A+B)[(A+B)'+C] [(B.(A'+B')]
then what do I do from here?
And this question just makes my balls sweat omg.. https://i.stack.imgur.com/OS9Uw.png
Been having trouble solving these questions of my homework. Thank You!