Stirling's approximation says that $$n!\sim\sqrt{2\pi n}\left(\dfrac{n}{e}\right)^n.$$ What is known about constants $c_1$ and $c_2$ such that $$c_1\sqrt{n}\left(\dfrac{n}{e}\right)^n\le n!\le c_2\sqrt{n}\left(\dfrac{n}{e}\right)^n$$ for all $n$? (If we only want the statement for any sufficiently large $n$, then any $c_1<\sqrt{2\pi}<c_2$ should work.)
2026-03-28 17:05:49.1774717549
Bounds on constant for Stirling approximation
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