How do you prove that $$ \lim_{t\to +\infty} (B_t+ct)=+\infty $$ almost surely?
$(B_t)_t$ is the standard Brownian Motion starting from $0$.
How do you prove that $$ \lim_{t\to +\infty} (B_t+ct)=+\infty $$ almost surely?
$(B_t)_t$ is the standard Brownian Motion starting from $0$.
Copyright © 2021 JogjaFile Inc.
There are several possible ways to prove it, depending on what you already know. If you know the strong law of large numbers for Brownian motion, which says that as $t \to \infty$, $\frac{B_t}{t} \to 0$ almost surely, then we have $$\frac{B_t + ct}{t} = \frac{B_t}{t} + c \to c\quad \text{a.s.}$$ Since $c > 0$ it follows that ${B_t + ct} \to +\infty$ a.s.