Brownian Motion with drift (stupid question)

392 Views Asked by At

How do you prove that $$ \lim_{t\to +\infty} (B_t+ct)=+\infty $$ almost surely?

$(B_t)_t$ is the standard Brownian Motion starting from $0$.

1

There are 1 best solutions below

7
On BEST ANSWER

There are several possible ways to prove it, depending on what you already know. If you know the strong law of large numbers for Brownian motion, which says that as $t \to \infty$, $\frac{B_t}{t} \to 0$ almost surely, then we have $$\frac{B_t + ct}{t} = \frac{B_t}{t} + c \to c\quad \text{a.s.}$$ Since $c > 0$ it follows that ${B_t + ct} \to +\infty$ a.s.