In the following figure, it is given three right angles and distances :
$ED = 3 $ , $ EB = 7$ and $CE = 5$.
Is it possible to calculate the length $EA$.
I tried using cyclic quadrilateral $ABCD$ and angles but couldn't find the expression.
In the following figure, it is given three right angles and distances :
$ED = 3 $ , $ EB = 7$ and $CE = 5$.
Is it possible to calculate the length $EA$.
I tried using cyclic quadrilateral $ABCD$ and angles but couldn't find the expression.
On
I'll solve it trigonometrically using essential concepts like The Law of sines and cosines. EA=5.8 See the link Below https://drive.google.com/file/d/1-OAlQzpJwEDPF7iwhxW575xLe-YbjR5L/view?usp=sharing
Yes it is. Use the coordinate system. Let $E=(0,0)$, $C = (0,5)$, $B= (-7,0)$ and $D=(3,0)$.
Now you have to calculate $A$ which is in the intersection of lines $AB$ and $AD$ (perpendiculars to $BC$ and $DC$).