
I solved this question and here are my answers, can you confirm whether they are correct?
(a) k = -2 (b) E(x)= 2ln(2) (c) Var(x) = 0.0782 (d) CDf = 2 - 2/x (e) P(X<=0.05) = 0 (f) pdf = e^(-x/2)

I solved this question and here are my answers, can you confirm whether they are correct?
(a) k = -2 (b) E(x)= 2ln(2) (c) Var(x) = 0.0782 (d) CDf = 2 - 2/x (e) P(X<=0.05) = 0 (f) pdf = e^(-x/2)
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The answer to (c) is $2 - (\ln4)^2$, you shouldn't just write the approximation.
Your answer to (d) is only correct for $1 \le x \le 2$, you also need to write down the remaining part.
Your density in part (f) is only correct for $0 \le x \le \ln 4$.
The rest is correct.