Calculating the joint density function

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Consider two random variables $X$ and $Y$. Let $Y=aX$ where $a$ is a constant. What is the joint Probability Density Function(PDF) of $X$ and $Y$?

The joint PDF is given by \begin{align*} \frac{\partial^2}{\partial x \partial y}P(X\leq x,Y \leq y) \end{align*} where \begin{align*} P(X\leq x,Y \leq y) &= P(X\leq x, X\leq y/a) \\ &= \begin{cases} P(X\leq x) & \text{, if } x<y/a\\ P(X\leq y/a) & \text{, if } x>y/a \end{cases} \end{align*} In both cases the partial derivative is zero? Am I missing something, are my calculations wrong or does the PDF not exist?

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$(X,aX)$ does not have a PDF, i.e. a density wrt the Lebesgue measure on $\mathbb R^2$.

This because the set $B=\{(x,ax)\mid x\in\mathbb R\}$ which satisfies $P((X,aX)\in B)=1$ has Lebesgue measure $0$.

If $f$ should function as a PDF then we get the contradiction:$$1=P((X,aX)\in B)=\int_Bf(x,y)dxdy=0$$