I've the sequence $\left(a_n\right)_{n \in \mathbb{N}}$ define as $a_0=a_1=1$ with $$ \forall n \in \mathbb{N}^{*}, \ a_{n+1}=a_n+\frac{a_{n-1}}{n+1}$$
I need to find the radius of convergence of $\displaystyle \sum_{ n \in \mathbb{N}}a_nx^n$. My trick was to define $$ w_n=\frac{a_{n+1}}{a_n} $$ Hence with the definition $$ w_n=1+\frac{1}{\left(n+1\right)w_{n-1}} $$ I've shown that if $(w_n)_{n \in \mathbb{N}}$ converges then it converges to $1$. How can I show that $(w_n)$ converges ? Any help ?
If $w_n =1+\frac{1}{\left(n+1\right)w_{n-1}} $, then $w_n > 1$.
Therefore $w_n < 1+\dfrac1{n+1}$.
Therefore $w_n \to 1$.