Can Cauchy's Theorem be used to solve a contour integral with singularities?

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I am having trouble trying to solve the following contour integral for an assignment: $\oint_C \left(z + \frac{1}{z^2}\right) \, dz$ where $C$ is the contour defined by $|z| = 2$. My professor is known for assigning tricky problems, and I wonder if this is one of them, as we have been specifically asked to use Cauchy's Theorem to solve it.

I know that typically Cauchy's Theorem is applied to analytic functions without singularities inside the contour of integration. However, the function $f(z) = z + \frac{1}{z^2}$ clearly has singularities at $z = 0$.

I have reviewed my notes and understand that the Cauchy Integral Formula is a common way to solve such integrals when there are singularities. However, I would like to clarify that I am specifically exploring whether there is a way to use Cauchy's Theorem for this exercise.

I appreciate in advance any help or advice you can provide. If you need more details about the exercise or any further clarification, please let me know.

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No, Cauchy's first integral theorem cannot be used directly here. It states that if $U$ is a simply connected domain, and $C$ is a closed curve in $U$ and $f$ is holomorphic on $U$, then $$\int_C fdz=0.$$ $C$ is obviously closed and $f$ is holomorphic on $C$ but we need to choose $U$. The problem is that we cannot choose $U$ to be simply connected without including $0$. However if we include $0$ then $f$ is not holomorphic on all of $U$.

In this case $f$ has a primitive on an open set containing the curve. In particular $$F(z)=\frac{z^2}2-\frac1z.$$ We can thus evaluate the integral as $$F(C(1))-F(C(0))=F(2)-F(2)=0$$ if we assume that $C$ starts and ends at the point $2$.