Can convergence interval of series differ by representation?

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(1)
$\begin{align}\frac{1+x}{1-x}&=(1+x)\frac{1}{1-x}\\ &=(1+x)\sum_{n=0}^\infty x^n\space(|x|<1)\\ &=\sum_{n=0}^\infty (1+x)x^n\space(|x|<1)\\ \end{align}$

But when $x=-1$, $\sum_{n=0}^\infty (1+x)x^n$ converges
So convergence interval is [-1,1)

(2)
$\begin{align}\frac{1+x}{1-x}&=\frac{1}{1-x}+\frac{x}{1-x}\\ &=\sum_{n=0}^\infty x^n + \sum_{n=0}^\infty x^{n+1} \space(|x|<1)\\ &=1+\sum_{n=1}^\infty x^n + \sum_{n=1}^\infty x^{n} \space(|x|<1)\\ &=1+2\sum_{n=1}^\infty x^n \space(|x|<1)\\ \end{align}$
So convergence interval is (-1, 1)

Series representation of (1) and (2) is different and convergence interval is different. Is this generally correct?

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It is correct, if you see them as series of functions. But you should be aware of the fact that your first series is not a power series, whereas the second one is.