This might be some kind of foundational assertion. Given any angle $\psi$ and $x\in\Bbb Z^+$ I'd like to see proof that:
$$\psi = \psi + 2x\pi$$
It's hard cause numerically this isn't true, but in the sense of angles it is. I specifically need this to make my proof based on more than my on personal assertion here: https://math.stackexchange.com/a/2144499/194115
Mathematically, it is not true that $\psi = \psi + 2x\pi$.
What is true is that, for any trig function, since they have a period of $2\pi$ (some of them, like $\tan$, $\pi$), that $f(\psi) = f(\psi + 2x\pi)$.