I know it's possible to perform a sphere eversion is $\mathbb R^3$, if we allow self-intersections.
My question is: it's possible to perform a sphere ($S^2$) eversion in $\mathbb R^4$, without self-intersection? If yes, how?
2026-02-22 20:36:23.1771792583
Sphere eversion in $\mathbb R^4$
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