Can normal vector be argument of the vector being surface integrated?

33 Views Asked by At

Given a scalar function (field?) $f(\mathbf{x})$ (where $\mathbf{x}=[x_1,x_2,x_3]$) with gradient

$$\nabla f= [f_{x_1},f_{x_2},f_{x_3}]$$

Where

$$f_{x_i}=\frac{\partial f}{\partial x_i}$$

And given

$$\nabla f \cdot \mathbf{x}=c$$

where $c$ is some constant,

Is there a closed surface such that the outward pointing normal vector is everywhere equal to the argument vector $\mathbf{x}$, so that:

$$\int \int_S \nabla f \cdot \mathbf{x} \:dS=cA$$

where $A$ is the area of the closed surface. And can this closed surface, if it exists, be arbitrarily chosen such that $A=1$ or $A=4\pi r^2$ as convenient, or is it uniquely determined?