Set of solutions of this inequality :
$$\log_2({ \space x ^2 - 1}) < 1$$
The answer given is :$$ \sqrt3 < x < - 1 \cup 1 < x < \sqrt3 . $$
2026-03-29 10:37:12.1774780632
Can't find the set of solutions
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$$\log_2(x^2-1)<1$$ it's $$0< x^2-1<2$$ or $$1<x^2<3$$ or $$1<|x|<\sqrt3,$$ which gives your answer.