F(x) = 0, if x < 1 F(x) = 1, if 1<=x<=2 F(x) = 0, if x>2
I think it could be, as long as the integral is 1. Any ideas?
2026-05-17 08:48:58.1779007738
Can this function be a density function of a continuous random variable X?
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Your function is the probability density function of a random variable distributed uniformly on the interval $[1,2]$.
As well as having an integral across the real numbers of $1$, a probability density function also needs to be non-negative. Your function has this property.