I want to know how to construct, thanks.(I'm a newbie to math)
2026-04-01 01:18:26.1775006306
Can we find a countable subset of the real numbers which give us an outer jordan measure 1 but lebesgue 0?
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Any set that is Jordan measurable has Jordan measure that agrees with its Lebesgue measure.
However, if you mean a set that has outer Jordan measure $1$ and Lebesgue measure $0$, consider $\Bbb Q \cap [0,1]$.