If a subset of the real line is uncountable and closed, does it have to contain a closed interval? Is there any theorem related to this?
2026-04-08 17:38:15.1775669895
Closed Subsets of the Real Line that are Uncountable
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No, this is not the case.
The Cantor set is the classic example. But it is true that if a subset of $\Bbb R$ is closed and uncountable, then it contains a copy of the Cantor set, in particular every closed uncountable subset of $\Bbb R$ has the same cardinality as $\Bbb R$ itself.