Prove or disprove:
$3^{3^{3^{3^{3...^3}}}}$ with 100 threes $>4^{4^{4^{4^{4...^4}}}}$ with 99 fours.
Taking logs is useless, and there seems to be no other way to compare. Thanks!
Prove or disprove:
$3^{3^{3^{3^{3...^3}}}}$ with 100 threes $>4^{4^{4^{4^{4...^4}}}}$ with 99 fours.
Taking logs is useless, and there seems to be no other way to compare. Thanks!
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It suffices to see that $3^3>6\times4$ and that
$$3^{6n}>6\times4^n$$
for all $n\ge1$. By induction this gives us:
$$3\uparrow\uparrow(n+1)>6(4\uparrow\uparrow n)$$
for all $n\ge1$.
Of course much better bounds can be given, but this suffices.