Comparison of Hilbert space tensor product and wedge product

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For Hilbert Spaces:

$$(|0\rangle + |1\rangle)\otimes (|0\rangle + |1\rangle) = |00\rangle + |01\rangle + |10\rangle + |11\rangle.$$

where all results are column vectors

\begin{eqnarray*} 0 &=& \langle 00|01\rangle, \\ &=& \langle 00|10\rangle, \\ &=& \langle 00|11\rangle, \end{eqnarray*}

etc. But for Geometric Algebra, the geometric product results in all orthogonal bivectors

$$(a_0 + a_1)*(b_0+b_1) = a_0\wedge b_0 + a_0\wedge b_1 + a_1\wedge b_0 + a_1\wedge b_1.$$

\begin{eqnarray*} 0 &=& \langle a_0\wedge b_0,a_0\wedge b_1\rangle, \\ &=& \langle a_0\wedge b_0,a_1\wedge b_0\rangle, \\ &=& \langle a_0\wedge b_0,a_1\wedge b_1\rangle, \end{eqnarray*}

etc. The questions is: Where did the bivectors go in the Hilbert space tensor product? this leads to different results for bell and magic states between the two representations.