Confusing angle-chasing question

Question

AB = BC = CD = DE = EF = FG = GA

Find angle GAB. Please, I want the correct answer. I know how to solve it, but I am getting confused by the number of triangles in it. I am getting different answer every time I solve it. Please tell the correct answer. Options:

a. 180/5 b. 60 c. 20 d. 180/7

Answer 1

let $\angle gab=x$, then we have:
1. $\angle acb=x$ (since ab=bc)
2. $\angle gfa=x$ (since gf=ga)
3. $\angle ebd=2x$ (external angle of $\triangle$abc)
4. $\angle edb=2x$ (since bc=cd)
5. $\angle fge=2x$ (external angle of $\triangle$agf)
6. $\angle feg=2x$ (since ef=fg)
7. $\angle efd=3x$ (external angle of $\triangle$aef)
8. $\angle edf=3x$ (since ef=de)
9. $\angle edc=\angle edf-\angle cdb=x$
10. $\angle ecd=3x$ (external angle of $\triangle$acd)
11. $\angle ced=3x$ (since de=ed)
12. $\angle fed=\angle ced-\angle gef=x$

Finally, looking at sum of angles in $\triangle$def, we get:
$x+3x+3x=180$

Solve this to find $x$.

Answer 2

Denote the unknown angle at $a$ by $\alpha$. Working along the figure it is easy to express any occurring angle in terms of $\alpha$, using only that the angles at the base of an isosceles triangle are equal and that the sum of the three angles of any triangle is $\pi$. You will find angles $\alpha$, $2\alpha$, $3\alpha$, $\pi-4\alpha$, and the like. Looking at the triangle $ade$ you will finally obtain an equation that can be solved for $\alpha$.