My attempt:
The missing frequency = 6 (from 50 games which represents total frequency)
Total number of tickets won by Adan = 203
Mean number of tickets won per game = $\frac{203}{50}=4.06$
From this point onwards I am lost, especially when I read this part of the question ' Aidan wants to exchange his ticket for a prize that costs 800 tickets. How many more games do you expect Aidan would have to play?'
Any help will be appreciated.
On
So he has played $50$ games already and amassed $203$ tickets. Then the number of games he is expected to play to get the $800$ tickets is the number of games it will take to get $597$ tickets. This is found by $\frac{597}{4.06} = 147.044$ but we want to round up because we assume we can't have an incomplete game, so the answer is he needs to play $148$ more games to amass the $597$ extra tickets to get to $800$
Basic approach. The question is worded a little oddly. I would at least have expected it to put "tickets" in the plural in that third sentence.
Be that as it may, I read it as asking how many further games do you expect Aidan to have to play—winning tickets at his current pace per game—to total $800$ tickets. I'm going to assume that you have correctly computed his current ticket total at $203$, in which case he needs $800-203 = 597$ more tickets. I will also assume that you've correctly computed his average ticket rate per game at $4.06$.
So the question is, how many games would he have to play, winning $4.06$ tickets per game, to win $597$ more tickets?