continuity of a function $f = (f_1,f_2)$ in a product topology if $f_1$ and $f_2$ are continous

325 Views Asked by At

Say $X$, $Y_1$ and $Y_2$ are topological spaces. Let $f_1 \; X \to Y_1$ and $f_2 \; X \to Y_2$.

If $f\; X \to Y_1 \times Y_2 $ $f(x) = (f_1(x), f_2(x))$

$Y_1 \times Y_2$ is a topological space with the product topology.

How do I prove that $f$ is continuous in $x$ if and only if $f_1$ and $f_2$ are continuous in $x$ ?

1

There are 1 best solutions below

5
On BEST ANSWER

That is almost the definition of the product topology (i. e. the product is defined such that the above holds).

Hints: (1) If $f$ is continuous, note that the projections $\pi_i \colon Y_1\times Y_2 \to Y_i$ are continuous.

(2) If the $f_i$ are continuous, note that the sets $U_1 \times U_2$, where $U_i\subseteq Y_i$ are open, form a base of the product topology. What is $f^{-1}[U_1 \times U_2]$?