Continuity of a function on a metric space and its consequences

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Let $f : X → Y$ be a given function, and suppose that $f^{-1}(C)$ is an open subset of $X$ whenever C is an open subset of $Y$ .

(a) Prove that $f$ is continuous on $X$.

(b) Prove that $f^{-1}(B)$ is a closed subset of $X$ whenever B is a closed subset of $Y$

(c) If $Y = \mathbb{R}$, and $f$ is continuous, and $a \in \mathbb{R}$, what kind of set is $A = \{x \in X : f(x) \leq a\}$? Justify your answer

I already solved part a, and my attempt for part (b) is:

$f^{−1}(B)$ = $(f^{−1}(B^c))^c$ ⋯ (1) ($E^c$ denoting the complement of $E$).

So if B is closed, then $B^c$ is open, $f^{−1}{(B^c)}$ is open and its complement is closed. This means $f^{−1}(B)$ is closed by (1).

But I'm finding trouble in solving part (c). Any help please?