I'm not sure what differentiates discrete from continuous systems in trying to prove certain properties of controllability. I have a chain of proofs from class that prove each other for a continuous system:
We'll call our system $ \Sigma = (A,B,C)$
1) $ \Sigma $ is controllable if $(A,B)$ is controllable
2) The Gramian control matrix $W_c(t) $ is positive definite
3) There does not exist $ x=Ty $ with det $\space T\neq0 $ such that
$T^{-1}AT=\begin{bmatrix} A_{11} \ A_{12} \\ 0 \ A_{22} \end{bmatrix}, \space T^{-1}B=\begin{bmatrix} B_1 \\ 0 \end{bmatrix}$
4) The Kalman rank condition is satisfied.
5) The PBH test is satisfied for rank$[A-\lambda I \space B]=n$ for all $\lambda \in \sigma(A)$ and for all $\lambda\in \mathbb{C}$
How is this applied to the discrete case?
I believe, not sure, this is all more or less the same discrete case. First all the system matrices need to be discretized [2].
Controllability, exactly the same [1].
I believe this still holds. The matrix equation stays the same $A W_c + W_c A^T = -BB^T$, only the integral gramian equation changes see [3].
I believe also still the same. Since we are now only working with the discretized system matrices.
Same, since we are now only working with the discretized system matrices.
Same, since we are now only working with the discretized system matrices.