Problem. Let $Z, Z_1, Z_2, \cdots, Z_n$ be non-negative R.V.s with integer values. Prove that $Z_n \to Z$ in distribution, i.f.f $Pr(Z_n=t) \to Pr(Z=t)$ for all non-negative $t \in N$.
I have read about the Portmanteau theorem which states that if $ E_n f \to Ef$, then $P_n \to P$, P being the probability measure. Does this theorem apply in this case? (I was thinking convergence in distribution implies convergence in expectation.) thanks in advance.
Indeed you can utilize the Portnamteau theorem. Let me prove that
To this end, we prove the following simple lemma:
Indeed, by using the identity$|x| = 2x_+ - x$, we have
$$ \sum_{t=0}^{\infty} \left| p_n - q_n \right| = \sum_{t=0}^{\infty} 2\left( p_n - q_n \right)_+ - \underbrace{\sum_{t=0}^{\infty} \left( p_n - q_n \right)}_{=0}. $$
Now we apply this lemma to our problem. Let $f$ be an arbitrary bounded continuous function on $\mathbb{R}$. Then with $\|f\|_{\sup} := \sup\{ |f(x)| : x \in \mathbb{R} \}$, we have
\begin{align*} \left| \mathsf{E}[f(Z)] - \mathsf{E}[f(Z_n)] \right| &= \left| \sum_{t=0}^{\infty} f(t) \left( \mathsf{P}[Z = t] - \mathsf{P}[Z_n = t] \right) \right| \\ &\leq \| f\|_{\sup} \sum_{t=0}^{\infty} \left| \mathsf{P}[Z = t] - \mathsf{P}[Z_n = t] \right| \\ &= 2 \| f\|_{\sup} \sum_{t=0}^{\infty} \left( \mathsf{P}[Z = t] - \mathsf{P}[Z_n = t] \right)_+ . \end{align*}
Now the summand, as function of $t \in \mathbb{N}_0$, is dominated by the integrable function $t \mapsto \mathsf{P}[Z = t]$ (with respect to the counting measure on $\mathbb{N}_0$, of course) and hence by the dominated convergence theorem,
$$ \lim_{n\to\infty} \sum_{t=0}^{\infty} \left( \mathsf{P}[Z = t] - \mathsf{P}[Z_n = t] \right)_+ = \sum_{t=0}^{\infty} \lim_{n\to\infty} \left( \mathsf{P}[Z = t] - \mathsf{P}[Z_n = t] \right)_+ = 0 $$
by the assumption. Therefore $\mathsf{E}[f(Z_n)] \to \mathsf{E}[f(Z)]$ as required, and since this is true for any bounded continuous $f$ on $\mathbb{R}$, the conclusion follows from the Portmanteau theorem.