Convergence of an exponent function

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Following the answer to this MSE question, it is claimed that we easily show the following convergence:

$$ \text{exp}(-\sqrt{\lambda}it + \lambda (e^{it/\sqrt{\lambda}}-1)) \rightarrow_{\lambda \rightarrow \infty} \exp\left(-\frac{t^2}{2}\right)$$

Which is proved by noting that the following expression holds:

$$ \exp\left(\frac{it}{\sqrt{\lambda}} \right) -1 = \frac{it}{\sqrt{\lambda}} - \frac{t^2}{2\lambda} + o(\lambda^{-1})$$

While I understand how the former was derived, my question is how does this prove the convergence?

Since in this case,

$$\lambda (e^{it/\sqrt{\lambda}}-1) =\lambda\frac{it}{\sqrt{\lambda}} - \frac{t^2}{2} + o(\lambda^{-1/2}) $$

And I can't see why the $\sqrt{\lambda} it$ member disappears at the limit here. Does it have to do anything with the imaginary part?

What am I missing?

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It follows that $$ \exp(-\sqrt{\lambda}it + \lambda (e^{it/\sqrt{\lambda}}-1))=\exp(-\sqrt{\lambda}it+\sqrt{\lambda}it-\frac{t^2}{2}+\lambda o(\lambda^{-1}))=\exp(-\frac{t^2}{2}+\lambda o(\lambda^{-1})). $$ We note that $$ \lambda o(\lambda^{-1})\stackrel{\lambda\to\infty}{\to}0 \implies \exp(-\frac{t^2}{2}+\lambda o(\lambda^{-1}))\stackrel{\lambda\to\infty}{\to}\exp(-t^2/2) $$ by continuity of the exponential function.