Determine if the series converges or diverges: $$\sum_{n=1}^\infty \frac{\ln(n)}{n \left|\sin(n)\right|} = $$
We know that
$$ \sum_{n=1}^\infty \frac{1}i = \text{Divergent} $$
$$ \sum_{n=1}^1 \ln(i )= 0 $$
How to solve this?
Determine if the series converges or diverges: $$\sum_{n=1}^\infty \frac{\ln(n)}{n \left|\sin(n)\right|} = $$
We know that
$$ \sum_{n=1}^\infty \frac{1}i = \text{Divergent} $$
$$ \sum_{n=1}^1 \ln(i )= 0 $$
How to solve this?
Another way: also note $\frac{\log n }{n|\sin n|} \geq \frac{\log n}{n}$. Now look at $\sum_{n=1}^{\infty}\frac{\log n }{n}$. By intergral test if the integral diverges, then the sum diverges too. $\int_{1}^{\infty} \frac{\log x dx}{x} = \left. \frac{ \log^{2} x}{2} |^{\infty}_{1}\right.=\infty$. The integral diverges, hence the sum diverges too. Since the original sum is lower-bounded by this one, by comparison test it diverges too.