Give a counter example to show the argument is not valid by using formulas from a particular structure interpreting the language.
$\forall x\exists y (r_1xy)$
$\forall y \exists x (r_2xy)$
then, $\forall x \exists y ((r_1xy)\wedge (r_2xy))$
Give a counter example to show the argument is not valid by using formulas from a particular structure interpreting the language.
$\forall x\exists y (r_1xy)$
$\forall y \exists x (r_2xy)$
then, $\forall x \exists y ((r_1xy)\wedge (r_2xy))$
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Let the universe be $\mathbb{N}$, $r_1$ denotes $=$, and $r_2$ denotes $\neq$.