cyclic quad, circle theorems, that came on my test

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I have a question from a geometry test.

AB is parallel to CD

trapezoid inscribed in a circle

I got Angle CBD = 180-x because angles on a straight line are equal.

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Since $ABCD$ is cyclic trapezoid it must be isosceles, so the $\angle CDB =x$.

Or $$ \angle CDB = 180-\angle DBA = \angle ACD$$