I have a question from a geometry test.
AB is parallel to CD
I got Angle CBD = 180-x because angles on a straight line are equal.
I have a question from a geometry test.
AB is parallel to CD
I got Angle CBD = 180-x because angles on a straight line are equal.
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Since $ABCD$ is cyclic trapezoid it must be isosceles, so the $\angle CDB =x$.
Or $$ \angle CDB = 180-\angle DBA = \angle ACD$$