Definition unramified local representation

126 Views Asked by At

We can define unramified representation of $GL(2,\mathbb Q_p$) as a representation $(\pi , V) $ such that $V^K\neq \{0\}$ for $K$ the maximal compact subgroup i.e. $GL(2,\mathbb Z_p)$.

However, I do not understand why this is called unramified.

What I want to see (hopefully) is some sort of connection with unramified extension. For example, a Galois representation is called unramified if its factors through the Galois group of the maximal unramified extension or equivalently, the quotient of the absolute Galois group with the inertia subgroup.

2

There are 2 best solutions below

0
On BEST ANSWER

Let $f$ be a modular form (normalised new eigenform), and $p$ a prime. Then the following are equivalent:

  1. The $GL_2(\mathbf{Q}_p)$-representation $\pi_p$ is unramified, where $\pi = \sideset{}{'}\bigotimes_\ell \pi_v$ is the automorphic representation associated to $f$.

  2. For some (equivalently every) prime $\ell \ne p$, the restriction of the $\ell$-adic Galois representation $\rho_{f, \ell}$ to a decomposition group at $p$ is an unramified representation of $Gal(\overline{\mathbf{Q}}_p / \mathbf{Q}_p)$.

The reason why (1) and (2) are equivalent is because each of them is equivalent to the much simpler statement:

  1. The level of $f$ is not divisible by $p$.

But the equivalence of (1) and (2) should give you some feel for why "unramified" is used for both concepts.

1
On

Local class field theory provides a natural isomorphism $GL_1(\mathbb Q_p) = \mathbb Q_p^\times \cong W_{\mathbb Q_p}^{ab}$ between the multiplicative group of $\mathbb Q_p$ and the abelianisation of the Weil group of $\mathbb Q_p$. Under this isomorphism, unramified characters of the abelianised Weil group correspond to unramified representations of $GL_1(\mathbb Q_p)$.