The dealership buys cars for $15000$. When the dealer sells each car for $25000$, she sells $24$ cars per month. For each reduction of $600$ in the selling price, the dealer sells $2$ more cars per month. Determine the number of cars sold in one month to maximize profit.
I know the cost function should be $c(x) = 15000x$ , but what is the revenue function?
The answer is $29$. Thanks for any help.
The revenue per car (RPC) is
$$\mbox{RPC} (x) = 25000 - 300 (x-24) = 32200 - 300 x$$
and, thus, the profit is
$$\mbox{Profit} (x) = (\mbox{RPC} (x) - 15000) x = 17200 x - 300 x^2$$
Differentiate and find where the derivative vanishes. If the maximiser is not an integer, round up and down. Choose the maximum of the two. That is where profit is maximized.