Consider the function $f(x)=kx^{2}-2kx+2.$
Find the values of $k$ if $kx^{2}+2>2kx$ for any value of $x$.
I am unsure how to start off this question. I thought it involves the discriminant but couldn't figure out which condition to apply. Any help will be appreciated.
I'm not sure if this is right...
please comment if it is wrong
i) $k>0$
$kx^2-2kx+2>0$
$D=k^2-2k<0$
$0<k<2$
ii) $k=0$
$2>0$ -> True
iii) $k<0$
$kx^2-2kx+2>0$ -> cannot be always true
Therefore, $0\leq k<2$