Suppose there is a right triangle where all side-lengths are integers. The distance from the circumcenter to the centroid of the triangle is 6.5.
Find the distance from the centroid to the incenter of the right triangle.
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I have found the solution to this problem.
First draw triangle ABC with AB being the hypotenuse. The circumcenter O is the midpoint of the hypotenuse. Centroid G is 2/3 of the way from right angle C to point O.
CO is now 19.5 and AB is 39. Pythagorean triples makes the legs 15 and 36 in length. With C being the origin, A becomes (0, 15), and B = (36, 0). O is now (18, 7.5) and G is (12, 5).
If we name the incenter of the triangle I and the inradius r we know that 15-r+36-r=39. Hence, r = 5 and I is (6, 6). Thus, by distance formula, GI is square root of 37.