Distributive laws and Absorption laws with negation

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I'm currently stumped because I can't seem to find a way though this proof I'm currently doing. I did notice because of this proof that I'm really not sure how to handle these two situations...

1) A situation where it looks like I can use absorption laws, but there's negation like so: $(p ∧ q) ∨ ¬p$

2) A situation where it looks like I can use distributive laws, but there's negation like so : $(p ∧ q) ∨ (¬p ∧ ¬r)$

Any clarification is much appreciated!

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  1. Absorption law cannot be applied.
    That is because not-p is neither p nor q.
    Use distributive law.

  2. Distributive can be used.
    Consider not-p as s and not-r as t and apply distributivity.
    Afterwards return s to not-p and t to not-r.